Question

Question 17. Saccharomyces cerevisiae (also called budding yeast or baker's yeast) normally makes LARGE colonies on the Petri dish. The fungus can exist as either a haploid or as a diploid. As a geneticist, you decide to isolate haploid mutants with altered size of colonies. You collect 6 such haploid mutants, which you arbitrarily name M1, M2, M3, M4, M5, and M6. To determine how many genes are represented by your mutants, you do a series of crosses resulting in diploids, i.e. you mate two haploid strains to produce a diploid strain. The complementation data are shown below. "+" indicates wild type (large) colony size and" - " indicates smaller (mutant) colony size. WT = wild type. I WT| m1 | m2 | M3 | MA | MS | 5 M2 M3 M4 M5 WT + M1 + M2 + + M3 + + + T M4 + + M5 + + M6

Answer 1

Ausi- - Mi single mutant produces medium colonies means here the Enzyme responsible for making medium colomes at present mutated gane in Mi Codes for ENF1 so that the Enzyme which forms here is ENZ2 so that ENZ2 acts on tay Colonies to make it medium when ma is mutated it produce tiny Colonies because & ENZ2 is not produced which converts tary colary to medium so the pathway is Model B. Please rate my Auswer.