The binding energy of titanium is 4.20 x 10 -18 J per electron and you shine light that has a frequency of 7.85 x 10 15 Hz. If 125 photons are absorbed by the Ti metal, then _____________ electrons should be ejected and each should have a Kinetic Energy of ________________. (SHOW WORKING)
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The binding energy of titanium is 4.20 x 10 -18 J per electron and you shine...
This question has multiple parts. Work all the parts to get the most points. The energy of a photon needed to cause ejection of an electron from a photoemissive metal is expressed as the sum of the binding energy of the electron plus the kinetic energy of the emitted electron. When photons of 4.40x107m light strike a calcium metal surface, electrons are ejected with a kinetic energy of 1.75x10-20 J. a Calculate the binding energy of the calcium electrons. b...
A metal surface has a minimum binding energy of 2.34x10-19 J/electron. An incident light of 345 nm wavelength was directed onto the metal. Answer the following questions: a. What is the frequency of the incident light? b. How much energy per photon is projected onto the metal surface? c. How much energy per mole is projected onto the metal surface? d. What is the kinetic energy given to one electron that is released from the metal from the photoelectric effect?...
The binding energy of electrons to a chromium metal surface is 7.21 × 10-19 J. What is the longest wavelength of light (in nm) that will eject electrons from chromiummetal? What frequency is required to give electrons with kinetic energy of 5.09E-19 J? What wavelength (in nm) is required to give electrons with kinetic energy of5.09E-19 J?
5. Find the kinetic energy of an electron whose de Broglie wavelength is 34.0 nm. J 6. Light with a frequency of 1.85 x 1015 Hz ejects electrons from the surface of zinc, which has a work function of 4.33 eV. What is the minimum de Broglie wavelength of the ejected electrons? nm
The binding energy for mercury is 435 kJ/mol of photons. (a) Calculate the threshold frequency. (b) Calculate the maximum velocity of the electrons ejected when light of wavelength 200 nm strikes the mercury. (KE = ½ mv2 , mass of electron = 9.109 x 10-31 kg)
1. Titanium metal requires a photon with a minimum energy of 6.94 x 10- J to emit electrons. a. What is the minimum frequency of light necessary to emit electrons from titanium via the photoelectric effect? b. What is the wavelength of this light? c Is it possible to eject electrons from titanium metal using visible light? 2. Calculate the energies of an electron in the hydrogen atom when n=2 and when n=6. Calculate the wavelength of the radiation released...
3 attempts left Check my work Be sure to answer all parts. Calculate the wavelength (in nm) of light with energy 1.61 x 10-20 J per photon. For light of wavelength 450 nm, calculate the number of photons per joule. x 10 photons/J Enter your answer in scientific notation. Determine the binding energy (in eV) of a metal if the kinetic energy possessed by an ejected electron (using one of the photons with wavelength 450 nm) is 2.93 x 10""'J....
Be sure to answer all parts. Calculate the wavelength (in nm) of light with energy 1.71 × 10−20 J per photon.m For light of wavelength 450 nm, calculate the number of photons per joule. photons/J Enter your answer in scientific notation. Determine the binding energy (in eV) of a metal if the kinetic energy possessed by an ejected electron (using one of the photons with wavelength 450 nm) is 2.38 × 10−19 J.
A He-Ne gas laser pulse with a wavelength of 594 nm contains 4.15 mJ of energy. a) How many photons are contained in one laser pulse? x10a photons a = b) Titanium metal has a work function (LaTeX: \Phi Φ ) of 4.33 eV. Is this laser pulse able to eject an electron from the surface of titanium? (yes / no) c) Show that this pulse can eject an electron from cesium (LaTeX: \Phi Φ = 1.97 eV). Upload a...
The electron binding energy for copper metal is 7.18 times 10^-19 J. Find the longest wavelength of light that could eject electrons from copper in a photoelectric effect experiment. E = 2.998 times 10^8 m/s h = 6.626 times 10^-34 Js nm