here,
q1 = 1 * 10^-8 C is at x1 = 1 cm = 0.01 m
q2 = 2 * 10^-8 C is at x2 = 2 cm = 0.02 m
q3 = 3 * 10^-8 C is at x3 = 3 cm = 0.03 m
the potential energy of this system , PE = K * q1 *q2/(x2 - x1) + K * q2 * q3/(x3 - x2) + K * q1 * q3 /( x3 - x1)
PE = 9 * 10^9 * 10^-8 * 10^-8 * ( 1*2/(0.02 - 0.01) + 2 * 3 /( 0.03 - 0.02) + 1 * 3 /(0.03 - 0.01)) J
PE = 8.55 * 10^-4 J
the potential energy of this system is 8.55 * 10^-4 J
Three charges lie on X-axis: 1x10" С at x 3x10*C 1 cm, 2 x 10.8 С...
Three particles lie on the x-axis: particle 1, with a charge of 1 x 10–8 C is at x = 1 cm, particle 2, with a charge of 2 x 10–8 C, is at x = 2 cm, and particle 3, with a charge of -3 x 10–8 C, is at x = 3 cm. The potential energy of this arrangement, relative to the potential energy for infinite separation, is:
Three particles lie on the x axis: particle 1, with a charge of 1 x 10–8 C is at x = 1 cm, particle 2, with a charge of 2 x 10–8 C, is at x = 2 cm, and particle 3, with a charge of -3 x 10–8 C, is at x = 3 cm. The potential energy of this arrangement, relative to the potential energy for infinite separation, is:
Three point charges lie on the x axis. Charge 1 (-2.4 μC ) is at the origin, charge 2 (+3.5 μC ) is at x =7.5 cm, and charge 3 (-1.7 μC ) is at x =11 cm. k=8.99×109N⋅m2/C2. What is the magnitude of the total force exerted on charge 2?
Three point charges are on the x axis: q1 is at the origin, q2 is at x = +2.00 m, and q3 is at x = +5.50 m. Find the electrostatic potential energy of this system of charges for the following charge values. (Assume the potential energy is zero when the charges are very far from each other.) (a) 1 2 3+4.00 c mJ (c) q1 = q3 = 3.00 pC and q2 =-3.00 pC
Two point charges lie on the x axis. A charge of -5.5 mu C is at the origin, and a charge of +9.5 mu C is at x = 10.0 cm. What is the net electric field at x = -4.0 cm? What is the net electric field at x = +4.0 cm?
Two point charges lie on the x axis. A charge of 6.5 μC is at the origin, and a charge of -9.3 μC is at x=10.0 cm. You may want to review (Page 671-675).Part AWhat is the net electric field at x=-4.0 cm?Part BWhat is the net electric field at x=+4.0 cm?
two charges lie in along the x-axis. Charge 1 is q1=1.3 c and charge 2 is q2=2.1 c. they are each a distance of d=0.011 m from the origin. What is the distance on the x-axis from the origin at which the electric field will be zero. given your answers in meters.
1) Three charges are placed along the x-axis. At -4 cm, a charge of +0.7 uc, at the origin, +1 uc, and at +6 cm, a charge of 2 uС. Find the net force (magnitude and direction) on the central charge. 2) In the above system, what is the electric field at the point on the x-axis x=-2 cm? What would be the acceleration experienced by an 80 nC charge with mass 107 kg?
Three point charges lie along the x-axis. Charge 1 has q1=6µC and is at x= -3.00cm. Charge 2 is at the origen and has q2= 1.50µC. Charge 3 is located at x3= 2.00cm and has a q3= 2.00µC. Calculate the magnitude and direction of the net electric force on q1, q2, and q3.
three point charges lie along the x axis as shown in the figure (no figure was given). the positive charge q1=15 mc is at x=2 m, the positive charge q2 =6 mc is at the origin, and the resultant force acting on q3 is 0. what is the x coordinate of q3?