Solution :
Given that 0.52,0.78,0.10,0.91,1.31,0.58,0.85
=> Mean x = sum of terms/number of terms
= 5.05/7
= 0.7214
= 0.721 (rounded)
=> Standard deviation s = 0.376 (rounded)
=> df = n - 1 = 6
=> for 95% confidence interval, t = 2.447
=> A 95% confidence interval of the population mean is
=> x +/- t*s/sqrt(n)
=> 0.721 +/- 2.447*0.376/sqrt(7)
=> 0.3732 < μ < 1.0688
=> 0.373 ppm < μ < 1.069
=> Yes, because it is possible that the mean is greater than 1 ppm. Also, at least one of the sample values exceeds 1 ppm, so at least some of the fish have too much mercury
A food safety guideline is that the mercury in fish should be below 1 part per...
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