(1) The final temperature in degree celsius of a liquid water will be given as :
we know that, Q = mice Cice (Tf - T0)
(6.99 x 106 J) = (10.5 kg) (2093 J/kg 0C) [Tf + (22.1 0C)]
(6.99 x 106 J) = (21976.5 J/0C) [Tf + (22.1 0C)]
Tf + (22.1 0C) = [(6.99 x 106 J) / (21976.5 J/0C)]
Tf = [(318.06 0C) - (22.1 0C)]
Tf = 295.96 0C
Tf 296 0C
(2) The mass of water that vaporizes which will be given as :
(Heat lost by mercury) = (Heat gained by water) + (Heat needed for phase change)
Qlost = Qgained + Qvaporization
mHg CHgT = mw CwT + m H
(3.96 kg) (140 J/kg 0C) [(204 - 100) 0C] = (0.212 kg) (4186 J/kg 0C) [(100 - 93.1) 0C] + m (333 x 103 kg)
(57657.6 J) - (6123.2 J)] = m (333 x 103 J/kg)
m = (51534.4 J) / (333 x 103 J/kg)
m = 0.154 kg
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