How to solve for A and a? Reaction energetics How are the standard free energy changes...
presente Organic Chemistry oudon The standard free energy of activation of one reaction A is 93.80 kJ mol-'(22.42 kcal mol-'). The standard free energy of activation of another reaction B is 74.80 kJ mol-'(17.88 kcal mol). Assume a temperature of 298 K and 1 M concentration. By what factor is one reaction faster than the other? Number Tools 10 Which reactior O Reaction A is faster. Reaction B is faster. Cannot be determined. O
13. How to calculation standard free energy change of a given biochemical reaction according to its equilibrium constant, Ked? What does it mean for a biochemical reaction when Ked'>, -, or <1? 20. Use an example to explain addition-elimination reactions.
13. How to calculation standard free energy change of a given biochemical reaction according to its equilibrium constant, K.? What does it mean for a biochemical reaction when K'>,, or <1? 20. Use an example to explain addition-elimination reactions.
A reaction Alaq) + Blaq) = Claq) has a standard free-energy change of -3.44 kJ/mol at 25°C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively? Number Number Number [A]= M [B] = [c]= 0 How would your answers above change if the reaction had a standard free-energy change of +3.44 kJ/mol? O O All concentrations would be lower. All...
A reaction has a standard free-energy change of-489 kJ/mol at 25 °C. What are the concentrations concentrations are 0.30 M, 0.40 M, and 0 M, respectively? of A, B, and C at equilibrium if, at the beginning of the reaction, their Number Number Number How would your answers above change if the reaction had a standard free-energy change of +4.89 kJ/mol? O There would be no change to the answers. O All concentrations would be higher. All concentrations would be...
A reaction A(aq) + B(aq) = C(aq) has a standard free-energy change of -3.38 kJ/mol at 25°C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and OM, respectively? [A] = [B] = 1C) = How would your answers change if the reaction had a standard free-energy change of +3.38 kJ/mol? There would be no change to the answers. O All concentrations would be...
A reaction A(aq) + B(aq) = C(aq) has a standard free-energy change of -3.06 kJ/mol at 25 °C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively? How would your answers change if the reaction had a standard free-energy change of +3.06 kJ/mol? O There would be less A and B but more C. All concentrations would be higher. There...
only do part (c) **please explain how to solve M^-2 The Haber process is used to make ammonia, N2(g) + 3H2(g) = 2NH3(g) a) Write down the condition for equilibrium for this reaction in terms of the concentrations of reactants and products. At 298 K, this reaction has AH° = -46 kJ mol"', and AS° = -100 J K-mol?. Assume that AH° and ASº are independent of temperature. At what temperature does AGº vanish, i.e. AG° = 0? (c) Under...
1. The simplest ammonia formation is from nitrogen and hydrogen. Consider the reversible reaction N2(g) + 3H2(g) → 2NH3(g) The standard enthaply and Gibbs free energy of formation one mole NH3 is ∆H◦ m = −46.11 kJ mol−1 and ∆G◦ m = −16.78 kJ mol−1 . (a) What is equilibrium constant at standard condition (25°C and 1 atm)? (b) What is equilibrium constant at 60°C and 1 atm? (c) What is the Gibbs free-energy change relative to that under standard...
Use the energy diagrams of the two reactions to answer the questions. Reaction A Reaction B Energy HHHH! (kJ/mol Energy 100 (kJ/mol) 50 Reaction progress Reaction progress What is the change in energy for reaction A? What is the change in energy for reaction B? AEX = kJ/mol AE/x = kJ/mol What is the activation energy for reaction A? What is the activation energy for reaction B? E = kJ/mol E.= kJ/mol Question 2 of 20 > For the reaction...