Homework Answers
For a definite quantity of ideal gas in transformation, the
quantity pV/T is invariant:
pV/T = constant, or
p1V1/T1 = p2V2/T2
V2 = V1(p1/p2)(T2/T1)
V1 = 1.20 cm^3
T2 = T1
p2 = 1 atm = 760 mm Hg
p1 = 760 mm Hg + 35000 mm H2O
the density of mercury with respect to H2O is 13.6
Therefore 35000 mm H2O = 35000/13.6 = 2574 mmHg
p1 = 760 + 2574 = 3334 mm Hg
V2 = V1(p1/p2)(T2/T1) = 1.20×(3334/760)×(1)
V2 = = 1.20 x 3.6 = 4.32 cm^3
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