Homework Answers
Answer. 6 as given that in one reaction 0.50 ul of template DNA is used. So for 5 reaction 0.50 × 5 = 2.5 ul of template DNA used. Also Total mix is 25 ul then for 5 reaction it will be 25 × 5 = 125 ul.
Also master mix (without template for 1 reaction ) is 24.5 up and master mix for 5 reaction = 122.5 ul.
So, To make individual reactions you would add 24.5 ul master mix to 0.50 ul of the template DNA.
Also for making 5 reaxtion you would add 122.5 ul master mix to 2.5 ul of the template DNA.
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How to solve for question#6?
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In each digestion tube you will be adding 10 ul DNA and 40 ul of
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You are setting up you own Master Mix for doing a Not1
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In each digestion tube you will be adding 10 ul DNA and 40 ul of
your Master mix.
You are given 10 x Not1 buffer, 10 ug/ul acetylated BSA, Not1
restiction enzyme 10 units/ul and sterile water.
How much of each of the 4 reagents would you use to make 500 ul of...
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Prepare a fragment of DNA to be cloned by PCR by preparing the
oligonucleotides received through dilutions. The DNA to be used as
a template is in a 50 ng/ul solution. The protocol is as
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VOLUME TO ADD FINAL CONCENTRATION 0.5 UM 0.5 M REAGENT 10 PM Forward Primer 10 PM Reverse Primer Thermoestable pol Master mix 2x Template DNA water 1x 100 ng.. Total volume 25 ul Information about the primers: Forward primer: 29.3 nmoles - 220 ug...
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solve for gel preparation and PCR mastermix calculations with
steps for understanding
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