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2. Chlorine gas can be prepared from treating hydrochloric acid with fluorine gas according to the following equation: F2+2 H

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Answer #1

20 2.2269 F2 =1252262) mol = 0.0586. mol. 75 ml of 1.50(M) HCP = 75x1950 mol HCl = 0,1125 mol HCl F2 (9) + 2 Hepcaq) + Cl269)2 - © Ahtoxn = Sah¢ [41269)] + 2x4H] [HF (29)]}-{{CF3LQ)] +2x44f [Hica) = [ {0 +2(-320-1)}-{ 0+26–166.994]}]«J = - 306.212 KJ

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