//////////// Calculate the double crossover interference value //////////
Homework Answers
Answer:
Hint: Always recombinant genotypes are smaller than the non-recombinant genotypes.
Hence, the parental (non-recombinant) genotypes is w+b+k+ / wbk
1).
If single crossover occurs between w+&b+
Normal combination: w+b+/wb
After crossover: w+b / wb+
w+b progeny= 3+33=36
wb+ progeny = 31+2=33
Total this progeny =69
Total progeny = 1107
The recombination frequency between w+&b+ = (number of recombinants/Total progeny) 100
RF = (69/1107)100 = 6.23%
2).
If single crossover occurs between b+&k+..
Normal combination: b+k+/bk
After crossover: b+k/bk+
b+k progeny= 67+2=69
bk+ progeny = 66+3=69
Total this progeny = 138
The recombination frequency between b+ & k+ = (number of recombinants/Total progeny) 100
RF = (138/1107)100 = 12.47%
3).
If single crossover occurs between w+&k+..
Normal combination: w+k+/wk
After crossover: w+k/wk+
w+k progeny= 67+33=100
wk+ progeny = 66+31=97
Total this progeny = 197
The recombination frequency between w+ & k+ = (number of recombinants/Total progeny) 100
RF = (197/1107)100 = 17.80%
Recombination frequency (%) = Distance between the genes (cM)
w--------6.23cM-----b---------12.47cM--------------k
Expected double crossover frequency = (RF between w & b) * (RF between b & k)
= 6.23% * 12.47% = 0.0078
As heterozygote order of genes is w+b+k+ & wbk its genotype after double crossovers are w+bk+ & wb+k.
The observed double crossover frequency = 3+2/1107 = 0.0045
Coefficient of Coincidence (COC) = Observed double crossover frequency / Expected double crossover frequency
= 0.0045 / 0.0078
= 0.58
Interference = 1-COC
=1-0.58
=0.42
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//////////// Calculate the double crossover interference value
//////////
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