For the reaction 2Fe3+ + 3I− ⇆ 2Fe2+ + I3− (all aq); The initial concentrations of...
2Fe3+ (aq) + 2I-(aq) → 2Fe2+ (aq) + I2(aq) What would be the cathode in this reaction? Question options: a. Fe3+ (aq) b. Fe2+ (aq) c. I2(aq) d. I-(aq)
What species is undergoing oxidation (if any) in the following reaction? Cl2(g) + 2Fe2+(aq) — 2CH(aq) + 2Fe3+(aq) O Fe2+ O Cl2 OCH O Fe3+
A voltaic cell utilizes the following reaction: 2Fe3+(aq)+H2(g)→2Fe2+(aq)+2H+(aq). emf of this cell under standard conditions E∘ = 0.771 V What is the emf for this cell when [Fe3+]= 3.70 M , PH2= 0.95 atm , [Fe2+]= 1.0×10−3 M , and the pH in both compartments is 3.95? Express your answer using two significant figures.
Use standard reduction potentials to calculate the equilibrium constant for the reaction: Fe2+(aq) + 2Fe2+(aq) —>Fe(s) + 2Fe3+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant: AGº for this reaction would be - than zero. Use standard reduction potentials to calculate the equilibrium constant for the reaction: Fe2+(aq) + Cu(s)—— Fe(s) + Cu2+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off...
1) Consider the following equilibrium: Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq) Initial concentrations: [Fe3+] = 0.590; [SCN-] = 1.239; [FeSCN2+] = 0 The equilibrium concentration of [FeSCN2+]eq = 0.454 M. What is the numerical value of KC for this equilibrium? KC = __________________ 2) Consider the following equilibrium: Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq) Initial concentrations: [Fe3+] = 0.370; [SCN-] = 0.777; [FeSCN2+] = 0 The equilibrium concentration of [FeSCN2+]eq = 0.285 M. What is the equilibrium concentration of Fe3+? [Fe3+]eq =...
The equilibrium constant for the reaction, 2Fe3+ (aq) + Hg22+(aq) 2Fe2+ (aq) + 2Hg2+ is Kc = 9.1 x 10-6 @298K a. What is ΔGo at this temperature? b. If reactants and products in their standard state concentrations (1M) are mixed, in which direction does the reaction proceed? Provide a numerical justification for your response. c. Calculate ΔG when [Fe3+] = 0.20 M, [Hg22+] = 0.010 M, [Fe2+] = 0.010 M, and [Hg2+] = 0.025 M. In which direction will the...
temp is : 298K QUESTION 9 Please show all work. For full credit provide equations used. Please use correct significant figures and correct units in answers. The equilibrium constant for the reaction, 2Fe3+ (aq) + Hg22+ (aq) = 2Fe2+ (aq) + 2Hg2+ is Kc = 9.1 x 10-6 @298K a. What is AGO at this temperature? b. If reactants and products in their standard state concentrations (1M) are mixed, in which direction does the reaction proceed? Provide a numerical justification...
Equilibrium Concentrations for a Simple Addition Reaction At a certain temperature K = 1.10x103 for the reaction: Fe3+(aq)SCN"(aq) FeSCN2+(aq) 5.00x102 mol of Fe(NO3)3 is added to 8.70x 10-1 L of 1.84 x 10-1 M KSCN. Neglecting any volume change and assuming that all species remain in solution--: Calculate the equilibrium concentration of Fe3+ (in mol/L) mol/L 1 pts 提交答案 Tries 0/8 Calculate the equilibrium concentration of SCN (in mol/L). mol/L 1 pts [提交答案 Tries 0/8 Calculate the equilibrium concentration of...
Use standard reduction potentials to calculate the equilibrium constant for the reaction: Cd2+(aq) + 2Fe2+(aq)Cd(s) + 2Fe3+(aq) Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant: _____G° for this reaction would be(greater/less) than zero
For each equilibrium sample, calculate the initial concentrations (assuming no reaction occurred) of SCN– and Fe3+ based on the dilution factors used. Enter the absorbance values for each sample. For the standard solution, assume that, when equilibrium is reached, the [FeSCN2+]eq is equal to [SCN–]ini. Why is this a good assumption? For the equilibrium solutions, calculate the [FeSCN2+]eq (Ceq) using Eq. 4. Using Eq. 5 and 6, calculate [Fe3+(aq)]eq and [SCN–(aq)]eq for each equilibrium solution. Calculate values for the equilibrium...