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What will be the size of storage, measured in bytes, needed to store a 16-second video at a 30-frame/second and a picture resolution of 256 by 256 pixels, assuming we are using a 24-bit RGB full color, with no compression.

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Answer #1

Solution:

We have 256 by 256 pixels picture resolution.

Also, given 24 bits for each pixel.

We then compute the amount of video memory required:

1. ? bytes = number of pixels * bytes per pixel

2. number of pixels = 256 * 256= 65,536

3. bytes per pixel = 24bits/pixel /(8bits/byte)=3 bytes / pixel

4. bytes of video RAM = 65,536 pixels * 3 bytes/pixel = 196608 bytes

Thus we need 1,96,608 bytes size of storage to store the given video as mentioned in the question

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