1) the heat capacity is the amount of heat absrobed by a substance in increaseing its temperature by 10C
Given: Heat absrobed = 3851 Joules
The increase in temperature = 43.3 0C
Heat capacity = Heat absorbed / increase in temperature = 3851 / 43.3 = 88.94 J / 0C
Specific heat of a substance= heat required to raise the temprature of one gram of substance by 10C
Given mass =371 g
So specific heat capacity = 88.94 J / 0C / 371g = 0.240J /g 0C
So the object is compsed of silver
2) Overall balanced equation will be
Cu(s) + 2Ag+(aq) ---> Cu+2(aq) + 2Ag(s)
3) The heat provided to ice first will be used for raising the temperature, if further heat is left then it will be used for conversion of ice to water (l) and rest for heating water
Heat given = 687 cal = 687 X 4.18 J = 2876.33 Joules
Heat given = heat absorbed = Mass of ice X specific heat of ice X change in temperature
Heat absorbed by ice = Q1 = 5 X 2.087 J/g 0C X change in temperature = 5 X 2.087 X (20-0) = 208.7 Joules
Heat absorbed in conversion of ice to water = Mass X Heating capacity = 5 X 333.6 J /g = 1668 Joules
Heat left = 2876.33 - (208.7 + 1668) = 999.63 Joules
This heat will be absrobed for raising the temperature of water
Heat = Mass of water X specific heat of water X change in temperature
999.63 = 5 X 4.184 X Change in temperature
Change in temperature = 47.78 0C
Final temperature of water = 47.78 0C
In 1987, a gargantuan iceherg broke away from the Ross Ioe Sheet in Antarctica It was...
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