A reaction has ΔrH∘=ΔrH∘= -116 kJmol−1 and ΔrS∘=ΔrS∘= 303 JK−1mol−1 . Part A At what temperature...

Question

Question

A reaction has ΔrH∘=ΔrH∘= -116 kJmol−1 and ΔrS∘=ΔrS∘= 303 JK−1mol−1 .

Part A

At what temperature is the change in entropy for the reaction equal to the change in entropy for the surroundings?

Answer 1

Answer #1

ΔrH∘= -116 kJmol−1 and ΔrS∘= 303 JK−1mol−1 .

$\Delta$ S⁰ = $\Delta$ S surr

$\Delta$ S⁰ = - $\Delta$ H⁰/T

T = - $\Delta$ H⁰/ $\Delta$ S⁰

= -*-116*10^3/303

= 382.84K >>>>>answer

Answer 2

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