What is ΔrS for a reaction that has ΔrH = -85.6 kJ mol-1 and ΔrG = 93.9 KJ mol-1 at 16.2 °C?
ΔG = 93.9 KJ/mol
ΔH = -85.6 KJ/mol
T= 16.2 oC
= (16.2+273) K
= 289.2 K
use:
ΔG = ΔH - T*ΔS
93.9 = -85.6 - 289.2 *ΔS
ΔS = -0.6207 KJ/mol.K
ΔS = -621 J/mol.K
Answer: -621 J/mol.K
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