Question

Let X1, X2, ..., Xn be a random sample from X which has pdf f(20) depending on a parameter \theta and

(i)  ((z(0 – 2) - )dxəz(47) = (el<)} (ii)  f(20) = (270) exp(-?/(20))

where -\infty < x < \infty . In both these two cases

a) write down the log-likelihood function and find a 1-dimensional sufficient statistic for \theta

b) find the score function and the maximum likelihood estimator of \theta

c) find the observed information and evaluate the Fisher information at \theta = 1.

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Answer #1

Solution: Given that, X; , X2, X.3.,X4,-Xn be a semnale random sample from x n and f(xb) = (203\2 exp{-} (x-1)} (-00<x<«). a)(6) we have We have to find the score function and the maximum likelihood estimator of O. NOW, log L(410) = un log 2 7 - noun- 11 - Thanking you — 11- --xx — PLZ ikke and support : _xx

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