What is the peak (maximum) power dissipated by a 150-W light bulb attached to a 120 V rms ac line?
And, if the bulb is rated 150 W at 240 V, then
at 120 V, i.e. half of 240 V,
P will get one-fourth.
apply power P = V^2/R
as Vmax = Vrms * sqrt 2
so P = 120*1.414)^2/(150)
P = 192 Watts
What is the peak (maximum) power dissipated by a 150-W light bulb attached to a 120...
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