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In a batch of 20 television picture tubes, 5 are known to be defective. What is...

In a batch of 20 television picture tubes, 5 are known to be defective. What is the probability that a random sample of 5 (without replacement) will result in each of the following?

Exactly 1 defective

No defectives

Two or fewer defectives

0 0
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Answer #1

p (defas Pive) L -0.25 n=5 X~ Bino (n=5, P=0,25) formula = P(x=29 = (*) ppcl-pja-* (3) - (9 p(x-1) = (5) la 25) (auss = 10.3

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