Question

= +0.7 m and released. The period is 3.9 s. At what (1 point) A block attached to a spring is displaced from equilibrium to the position positions and times during the first complete cycle do the following occur? a) v = 0.5 - Vmax, where Umax is the maximum speed? First position: m First time: Second position: m Second time: Third position: m Third time: Fourth position: m Fourth time: b) al = 0.5 . Qmax, where @max is the maximum magnitude of the acceleration? First position: m First time: Second position: m Second time: Third position: m Third time: Fourth position: m Fourth time:

Answer 1

T= 3.95 x=0 equilibrin A 0.7 m = a√ A²X2 . V, 0.50 max Vmax = AW . An - X J A²x2 A2_x²= 1² x=3A² an= √3 A 63 x 0.7=0.606. t/ ha to k 1/12, x=0.606 n ato.i L 0.606 M=-0.7 to M. Argut . 33 coswt . wt = I at = T = y y 27 - To First position n. 0-606m first time = 0+3255 second position 12-0.606m second time = .1.625s. 3rd position n=-0.606m third time = 2.2755 - 4th position a=40.606 m. 4th time = 3.5755.

1 b) a sw²x a. 0.5 aman 0.5W²A ia=0's wat 9) w-, 0'S - A az A/ s 0.35 x= Acos at A LA Wt tot _a t = t - T T I - 3 w 320 1/6 1/12 to -0.7 -0.35 T +0.25 -707 No first position and position and position 4th position a 0.35m 1² time = 0.655 n=-0.35m and time = 1.35 =-0135 m 3rd time = 2.65 n = +0.35m 4th Hone= 3.255.