Given
Lenth of one strip L = 0.60 m
Thickness of one strip t = 0.12 x 10-3 m
Known
Linear thermal expansionn coefficient of brass αB = 19 x 10-6 K-1
Linear thermal expansionn coefficient of brass αs = 13 x 10-6 K-1
Solution
The Difference in radius r1 - r2 = t = 0.12 x 10-3 m
The new length of the srips are equal to the circumference of the circles.
Circumference of brass circle SB = 2πr1
Circumference of steel circle SS = 2πr2
Change in length of the brass sripe
ΔL = αBLΔT
2πr1 - L = αBLΔT ….(1)
Change in length of the steel sripe
ΔL = αsLΔT
2πr2- L = αsLΔT ….(2)
2πr1 -2πr2 = (αB -αs )LΔT
2π(r1 -r2 ) = (αB -αs )LΔT
2πt = (αB -αs )LΔT
ΔT = 2πt/(αB -αs )L
ΔT = 2 x 3.14 x 0.12 x 10-3 / ( 19 x 10-6- 13 x 10-6) x 0.60
ΔT = 209 OC
An increase in temperature by 209 oC would form a full circle
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