a constant torque of 10m•N is applied to the rim of a 8.0-kg uniform disk of...
Homework Answers
torque = 10 Nm
mass m = 8 kg
radius = 0.15 m
angular displacemet theta = 2 revolution = 2*2*pi rad
work done = change in KE
torque *displacemenet = 0.5*I*(w2^2-w1^2)
10*2*2*pi = 0.5*(1/2)*8*0.15^2*(w2^2-0^2)
w2 = 52.844 rad/s <<----------answer
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