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#include #include <stdio.h> <string.h> Return the result of appending the characters in s2 to s1 Assumption: enough space has been allocated for sl to store the extra characters. char* append (char s1[ ], char s2[ ]) int sllenstrlen (s1); int s2lenstrlen (s2) int k; for (k=0; k<s21en; k++) { sl [kts11en] = s2 [k] ; return sl; int main () char strl [10]; char str2 [10]; while (1) printf strl -) if (gets (strl)) ( return 0 printf str2-) if (gets (str2)) ( return 0 printf (The result of appending str2 to str1 is %s.\n, append (strl, str2)); return 0;

I NEED HELP FINDING THE BUG IN THIS CODE USING THE GDB

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COB enline Debugger | Compie X+ https://www.onlinegdb.com SPONSOR I-Link OnlineGDB bota anlinc compiler and dcbugger for ir++ Run Debug Stop Share H Save Language C nain c code, compile, run. debug. share. 1 #include <stdio.h> #include <string.h> 3 char append (char s1[],char s2])t IDE My Projects Lean Programming Programming Questions Sign Up Login int s1len strlen(s1); int s21enstrlen(s2); int k; for(k:0; k%21enzk++){ 18 return s1; 12 int main() 13- 14 15 20,5K char str1[10]: char str2[101; 16-while(1) 17 18 19 26 21 printf(stri-); if(lgets (str1))1 slack return e printf(str2-); if(lgets (str2))1 Ils Learrmwork, bul simpler, more pleasant and more productive. 23 24 25 26 27 28 return e b: printf(The result of appending str2 to str1 is %s.\n,append(str1,str2)); return ; input strl- John L2 Doe Activate Windows Go to Settings to activate Window About FAQ-Blog Temes af LIesaes-Corna Us-GDB strl-I utonal Gredits 2018 GDB OnlineI have written the same code and executed it in GDB compiler. There are no errors in the code it's working fine as you can see in the above screenshot!!

//any query, post in the comment section.

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