What is the minimum work needed to push a 1075 kg car 330 m up along a 17.5° incline?
(a) Ignore friction.
J
(b) Assume the effective coefficient of friction retarding the car
is 0.20?
J
a)
from the force diagram
F = mg Sin17.5
F = 1075 x 9.8 Sin17.5
F = 3168 N
work done = F d = 3168 x 330 = 1.1 x 106 J
b)
fk = u Fn
fk = u mg cos17.5
from the force diagram
F = mg Sin17.5 + mg cos17.5
F = 1075 x 9.8 Sin17.5 + (0.2) (1075 x 9.8) Cos17.5
F = 5177.42 N
work done = F d = 5177.42 x 330 = 1.71 x 106 J
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