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1) Design truth table, POS/SOP, circuit and simplify form. (only do the highlighted one) 1 Sum...
5) Design truth table, POS/SOP, circuit and simplify form. (only do the highlighted one) 5 Sum Term е ST D+C+ B+ A 1 0 D +C+B+ A D+C+B'+ A D+C+B'+ A 1 0 0 D+C+ B+A 0 D+ C'+ B + A D+C'+B'+A 1 D+C+B'+ A D' +C+B+A 0 1 D'+ C+ B A 7 Sum Terms 3 Product Terms
7) Design truth table, POS/SOP, circuit and simplify form. (only do the highlighted one) oloa 1 Sum Term ST D + C + B +A D + C + B + A D + C + B'+ A D + C + B' + A' D + C' + B + A D + C' + B + A' D + C + B'+ A D + C + B' + A D' + C + B + A D'...
4) design truth table, POS, circuit and simplify form 6 Sum Terms PT D'.C.B.A' D'.C.B.A. D'.C.B.A' D'.C.B. A D'.C.B.A D'.C.B.A D'.C.B.A' D'.C.B.A D.C.B.A' D.C.B'. A 1 1 O 1 O 6 Product Terms 4 Sum Terms
Solve the following problems: 1.(4 points) Design the simplest sum-of-products circuit that implements the function Write the truth table, canonical SOP form, minimal form, and cost. 2.(4 points) Design the simplest product-of-sums circuit that implements the function f(x1, X2, X3 ) = II M(2,3,6). Write the truth table, canonical POS form, minimal form, and cost. 3.(2 point) Design a circuit that implements the simplest sum-of-products circuit that implements the function ing only NAND gates. Show all work, including logic networks.
Question 2 1. Formulate the minimized SOP and POS Boolean expression for the following truth table using Karnaugh map techniques. Out of the SOP and POS implementations, which is cheaper in terms of number of transistors? You can assume two transistors per input for a gate. (10 points) A B C Output 0 0 0 1 1 0 0 1 0 1 0 0 0 1 0 1 1
3. For the following circuit: B a. Give the truth table for F. b. Complete the following K-map and use it to give the minimized POS form for F(A,B,C). CIAB 00 01 11 10 C. Use boolean axioms and theorems on POS expression obtained in (b) to get the SOP form. The final SOP expression should have a maximum of two terms. d. Draw the logic circuit for the SOP form.
1.) Write a Boolean equation in sum-of-products (SoP) canonical form for each of the truth tables: A B C DY 0 0 00 1 0 0 01 0 0 0 01 0 0 11 0 1000 0 1 01 0 0 1 1 0 1 0 1 1 1 0 1 0 0 1 1 0 101 0 1 11 1 0 0 1 1 0 1 0 1 1 01 1 1 10 0 0 1 1 0 100...
4. Please convert the SOP Boolean Expression to Cannoncial Standard POS form and its shorthand form by hand and by using a truth table. (A*~B * C) + ("A *~B) + (A * B * C * D)
X 1. Determine the truth table for the above circuit. A B C 0 0 0 0 0 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 111 2. Determine the Karnaugh Map for the above circuit and do both an SOP minimization (the left KAI) and a POS minimization (the right KM). Write the minimized Boolean expressions below the corresponding Karnaugh Map BC ВС 00 01 11 10 00 01 11 10 0...
1- Write the unsimplified POS Boolean equation for F from the Truth Table. F = 2- Write the unsimplified SOP Boolean equation for F' from the Truth Table. F' = 3- Using only DeMorgan’s Theorem (show steps) and the unsimplified POS Boolean equation, find. maxterms minterms 0 1 0 1 0 1 10 101