Question

16). The pil of a solution pieparod by mixing 20.00ml, of 0 10M Nits wth What woald be he Ks for NI13? Phee d a yoar work 17). Suppose yuu titrale 4000 ml、of 0.100 M A, with 0.100M las a) If at half eyuivulence poine thaeu 95 what is the Ka? b) What is the ptl an the oquivadence point 2) c). What would be the pH afier adding 30 mL.of o.100M H,SOs to the above soltion ot 40.0 mi o 0 100 M A

Answer 1

Given picture having blur effect so the question is not visible clearly. Please upload a clear picture of question always.

Whatever I understood from visible part of question I'm answering here:-

(a) As we know that in potentiometric titration curve half equivalence point pH EpKa value and hence the pKa value -9.5 and we know that pKa -log Ka and hence Ka 10-9.5 (b) We know that M1V1-M2V2 M1 - 0.10M V1 -40.0mL M2 0.10M Hence V2 -M1V1/M2 -(0.1 X40.0)/0.1 -40.0mL pH equivalence point uffer regien half alf equivalence point So the volume of base at the equivalence point is 400m pHEpKa Volume of base