Question

Zoom 125% Insert Table Chart Text Shape Media Comment For each of the following studies, conduct the 4 steps of hypothesis testing with the z test. If you find it helpful, you can use the boxes on the right to sketch out a normal curve, plot your crew, shade in the region of rejection, and plot your job to help you visualize your decision. Benodo owns an ACT Prep company. He believes that students who take his prep course will score differently on the ACT than the national average. He randomly selects a sample of 25 (N = 25) of his prep course graduates and finds their mean ACT score to be 19.90. The national average is 21 ( 21,0 = 5.4). Do Renado's students score differently on the ACT than average? 1. STEP 1: Identify your null and alternative hypotheses. He: HA 2. STEP 2: Set up your decision rule. Directional or non-directional? One or two-tailed? What critical will you use? What does that mean about where the region of rejection is? If www falls in the region of rejection, what does that say about the likelihood of getting that value by chance alone? • eren 655 words alculate your test statistie. buro

please do all of the steps

Answer 1

Step is- Ho: M = 21 e toro s Hail &21 oH toive torre new Step 2 sur leur tojer at li uw The test is 2 failed z test The hypothesis is non directional Ecritical = + 1.46 coe o = The rejection region - We reject Ho for given sample at 5% level of significance if it observed value of test statistic 5-1.96 or71.96. nie. if Zobtained 5-1.96 ore zobtained > 1.96 we seeject to Step 3:- Test Statistic 19.90-21 Zobtained 219.90 Mo=20 2514 na25 =-1-0185 (round to 4 deanals)

4. As Zobtaind is not less than -1.96 we cannot reject Ho. S & M H We fail to reject null hypotheses. ats treats utt. est pvalue zaxP( ZY Zobtained ; Z HON 1031) = 2x [1- (4.0185)] =0. 308 4 404 - = bis This value is probability of getting Zobtained non nevie rot ott tout This pvalue >0.05. loved 17 ST- Conclusion & The prep course did not score significantly different than average student.

If there is any understanding problem regarding this please feel free to ask any doubt in comment box. Thank you.