Here ,
self inductance , L = 3 H
potential , V = 7.5 V
let the current at t =5.8 s is I
V = L * change in current/time
7.5 = 3 * (I - 3.5)/(5.8 - 5.2)
solving for I
I = 5 A
the current at 5.8 s is 5 A
A coil constituting a 3.0-henry (3 V/(A/s)) self-inductance is connected between terminals A and B whose...
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