Question

2. How many oxygen atoms are in 50 grams of aluminum sulfate Al2(SO4)3? Fill in the stoichiometric pathway with the information from this problem. Show the stoichiometric calculation for this problem.

Answer 1

dram mass Moles & molar mags = Al2(SO4)3 in 50 grams No. of moles of molarmass = 342.159/mol moles : so 342.15 = 0.146 mol since one mole of Ala (sou)3 has 12 moles of oxygen . - so 0.146 moles of Ala (sou) has 12 x0.146 = 1.75 moles → No. of atoms. Moles Moles = = 6.02 X 1023 - so, No. of oxygen atoms -> No. of oxygen atoms 1.15- 6.02 x 1023 No. of oxygen atoms = 1075 X 6.02 x 1023 = 10:55 X1023 atoms = (1005x1024 atoms