Two springs are hooked together end to end. When a 4.8-kg brick is suspended from one...
Two springs are hooked together end to end. When a 4.8-kg brick is suspended from one end of the combination, the combination stretches 0.15 m beyond its relaxed length. What is the spring constant of the combination? If the top spring stretches 0.10 m, what is the spring constant of each spring?
Homework Answers
when two springs are in series
requvalent spring constant 1/keq=1/k1+1/k2
keq=k1k2/k1+k2
total stretch is 0.15m
f=kx=mg
keq=4.8*9.8/0.15=313.6 N/m
if top spring stretches 0.10 m
k1 = mg / l
k1=4.8*9.8/0.10
k1=470.4 N/m
1/k2=1/313.6-1/470.4
k2= 940.8 N/m
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