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Two objects of different masses are suspended from two springs that have the same spring constant. The heavier of the two obj
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Answer #1

Frequency and period are inversely related. The highest frequency will have the shortest (smallest) period. Both springs have the same spring constant; only the suspended mass (m) is different. A spring with a smaller suspended mass will have a shorter period. This is consistent with the equation for period.

f = 1/T

since T = 2\pi(m/K) ^{1/2}​​​​​​

So the greater the two objects of the greater the equilibrium point beyond its spring farther.

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