Mean = = 177.4
Standard deviation = = 36.3
Sample size = n = 60
We have to find P( > 145)
For finding this probability we have to find z score.
That is we have to find P(Z > - 6.91)
P(Z > - 6.91) = 1 - P(Z < - 6.91) = 1 - 0.000 = 1.0000
Round to four decimal places as needed.) ol
□(Round to four decimal places as needed) DRoundtofour decinal places as needed) O Type here to
0-19 21 145 390 1316 Round to four decimal places as needed 0-19 21 145 390 1316 Round to four decimal places as needed
a) The probability is (Round to four decimal places as needed.) B) the store takes in at most $. ? (Round to two decimal places as needed.) A grocery store's receipts show that Sunday customer purchases have a skewed distribution with a mean of $33 and a standard deviation of $19. Suppose the store had 312 customers this Sunday. a) Estimate the probability that the store's revenues were at least $10,800 b) If, on a typical Sunday, the store serves...
Round to four decimal places as needed. Thank you! Assume a member is selected at random from the population represented by the graph. Find the probability that the member selected at random is from the shaded area of the graph. Assume the variable x is normally distributed SAT Critical Reading Scores 200<x<375 u = 506 o = 123 200 375 800 Score The probability that the member selected at random is from the shaded area of the graph is (Round...
6.2.11-T The area of the shaded region is (Round ข๐ four decimal places as needed.)
Compute the correlation for X and Y. (Round to four decimal places as needed.) Ply) X 2 0.15 0.40 Y 1 0.35 0.10 0 0.50 0.50 1 P(x) 0.45 0.55
The probability is Round to four decimal places as needed.) b. it 16 adult females are randomly selected, find the probability that they have puise rates with a mean less then 78 beats per minute The probability is Round to four decimal places as needed.) c. Why can the normal distribution be used in part (b), evon though the samplo size does not xcoed 30 O A. Sinoe the distribution is of sample means, not individuals, the disibution a normal...
(a) The probability that both wil be nervous around strangers is (Round to four decimal places as needed) (b) The probability that at least one person is nervous around strangers a (Round to four decimal places as needed.)
3.4.14 Perform the indicated calculation. 5P2 10P4 5P2 10P4 (Round to four decimal places as needed.)