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Question Help Determine the area under the standard normal curve that lies between (a)Z = -0.56 and Z=0.56, (b) Z=-0.25 and 2
the Normal Curve TABLE V Standard Normal Distribution 10* 70* 0 PO SO 90° 20* 80* 60 80000 0000 80000 80000 80000 0000 0000 1
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Answer #1

a)

= P(-0.56 <= z <= 0.56) = P(z <= 0.56) - P(z <= -0.56)
= 0.7123 - 0.2877
= 0.4246

b)

= P(-0.25 <= z <= 0) = P(z <= 0) - P(z <= -0.25)
= 0.5 - 0.4013
= 0.0987


c)

= P(-2.25 <= z <= -0.93) = P(z <= -0.93) - P(z <= -2.25)
= 0.1762 - 0.0122
= 0.164

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