Question

1 out of A wheel has an inner radius Ry = 0.5 m and an outer radius R2 = 1 m. The wheel is able to rotate around an axis that passes through its center and perpendicular to its plane. Two forces F = 20 N and F2 = 8 N act on the wheel as shown in the figure below. The magnitude of the net torque (in N.m) acting on the wheel about the rotation axis is: →F2 a) 2 b) 3 c) 4 d) 5 e) 6 iR2 R1 F1

Answer 1

$Torque\: T_{1} = r_{1}\times F_{1} = (0.5m)(20N) = 10 Nm\: (counterclockwise)$

Torque T2 = r2 X F2 = (lm) (8N) = 8Nm (clockwise)

Net Torque = $\left |T_{1}- T_{2} \right | = \left | (10Nm)-(8Nm) \right | = 2Nm$

Thus, Option a) 2 is the answer.