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Using a recurrence relation, prove that the time complexity of the binary search is O(log n)....

Using a recurrence relation, prove that the time complexity of the binary search is O(log n). You can use ^ operator to represent exponentiation operation. For example, 2^n represents 2 raised to the power of n.

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Answer #1

let n=2k Recurrence Relation 7(n) = + (/2) + 1 -> TV - Ten + + le = )! => Kalogn >T() = T (ha) + or tan) = T(1) + logn The )

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