Part C 0.175 m MgF2 Calculate the boiling point of the solution in part C, assuming complete dissociation.
Tf = -Kf*m*i
i = Mg+2 and 2 F- = 3 ions
kf = -1.86
dTf 0 -1.86*0.175*3 = -0.9765
TF = -0.9765°C
Part C 0.175 m MgF2 Calculate the boiling point of the solution in part C, assuming...
Assuming 100% dissociation, calculate the freezing point
(Tf) and boiling point (Tb)
of 2.32 m K3PO4(aq). Colligative
constants can be found in the chempendix.
Question 16 of 19> Assuming 100% dissociation, calculate the freezing point (T) and boiling point (Th) of 2.32 m K3PO4(aq). Colligative constants can be found in the chempendix "С Ть — "С
Question 16 of 19> Assuming 100% dissociation, calculate the freezing point (T) and boiling point (Th) of 2.32 m K3PO4(aq). Colligative constants can be...
Assuming 100% dissociation, calculate the freezing point and boiling point of 2.97 m AgNO3(aq).
Estimate the boiling point elevation of 0.39 m NaCl(aq), assuming it undergoes complete dissociation. The boiling point constant of water is 0.51 K · kg/mol. Answer in units of ◦C.
DO
NOT ANSWER THIS QUESTION!!!
Calculate the boiling point of a 4.5 m solution of Na2SO4 in water (assume 100% dissociation, Kb (H2O) = 0.52 °C/m).
Assuming 100% dissociation, calculate the freezing point (T) and boiling point (T) of 3.04 m AgNO, (aq). Colligative constants can be found in the chempendix.
Assuming 100% dissociation, calculate the freezing point and boiling point of 2.45 m AgNO3(aq). Constants may be found here.
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- Part C Calculate the freezing point of a solution containing 61.6 % KCl by mass (in water). Express your answer using two significant figures. V ALQ R O ? Tf= Submit Request Answer Part D Calculate the boiling point of a solution above. O ACQ* o ? Tb = Submit Request Answer Part E Calculate the freezing point of a solution containing 3.14 m MgF2. IVO AQ R o 2 ? T4 = Submit Request Answer Part F Calculate...
Assuming 100% dissociation, calculate the freezing point and boiling point of 2.11 m Na2SO4(aq). Constants may be found here. Solvent Formula Kf value* (°C/m) Normal freezing point (°C) Kb value (°C/m) Normal boiling point (°C) water H2O 1.86 0.00 0.512 100.00 benzene C6H6 5.12 5.49 2.53 80.1 cyclohexane C6H12 20.8 6.59 2.92 80.7 ethanol C2H6O 1.99 –117.3 1.22 78.4 carbon tetrachloride CCl4 29.8 –22.9 5.03 76.8 camphor C10H16O 37.8 176
Assuming 100% dissociation, calculate the freezing point ( T f ) and boiling point ( T b ) of 1.98 m AgNO 3 ( aq ) . Colligative constants can be found in the chempendix