What is the mass of 4.5 moles of magnesium sulfate?
No of moles = mass/molecularmass
mass = No of moles * molarmass
Molarmass of MgSO4 = 120.3676 g/mol
No of moles = 4.5
Mass of MgSO4= 4.5*120.3676 = 541.6542 grams
No of moles = mass/molecularmass
mass = No of moles * molarmass
Molarmass of MgSO4= 120.366 g/mol
No of moles = 4.5
Mass of NaI = 4.5*120.366 =541.647 grams
No of moles = mass/molecularmass
mass = No of moles * molarmass
Molarmass of MgSO4 = 120.366 g/mol
No of moles = 4.5
Mass of NaI = 4.5*120.366 = 541.647 grams
A. calculate moles of magnesium sulfate
b.calculate moles of water
c. The ratio of moles water: moles of magnesium sulfate.
d. Identify any potential sources of error.
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A 1.232 g sample of a magnesium sulfate hydrate is heated until its final mass is 0.602 g. What is the formula of the hydrate? Note: the molar mass of MgSO4 is 120.4 g/mol and the molar mass of water is 18.0 g/mol. MgSO4.5H20 a. O b. MgSO4.7H20 O c. MgSO4:3H20 d. MgSO4:H20