Question

(6%) Problem 9: During an ice show, a 65-kg skater leaps into the air and is caught by an initially stationary 87.5 kg skater. A 50% Part (a) What is their final speed, in meters per second, assuming negligible friction and that the 65 kg skater's initial horizontal speed is 4.25 m/s? > A 50% Part (b) How much kinetic energy is lost, in joules? Grade Summary AKElost = 1 Deductions 0% Potential 1000.

Answer 1

A)

Using law of conservation of momentum,

m1 v1 + m2v2 = (m1 + m2) v

(65 x 4.25) + 0 = (65 + 87.5) v

Velocity, v = 1.81 m/s

B)

Initial energy, E1 = 0.5 x 65 x 4.25^2 = 587.03 J

Final energy, E2 = 0.5 (65 + 87.5) x 1.81^2 = 249.8 J

Change = E1 - E2 = 337.2 J

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