In given balanced reaction,
3 Moles of calcium are reacted with 2 Moles of phosphoric acid.
Therefore for 1.372 Moles of calcium required
= (1.372 Mole Ca x 2 Mole H2PO4)/3mole Ca
= 2.744 / 3
= 0.914 Moles of phosphoric acid.
Therefore, for complete reaction of 1.372 Moles of calcium metal require 0.914 Moles of phosphoric acid.
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