Question

Aqueous calcium chloride reacts with aqueous silver nitrate according to the following balanced chemical equation:

CaCl₂(aq) + 2AgNO₃(aq) => 2AgCl(s) + Ca(NO₃)₂(aq)

a. How many moles of AgCl(s) are made if 0.557 L of 0.235 M CaCl₂ react with excess AgNO₃?

b. How many grams of AgCl are made?

Answer 1

Ans:

a) Number of moles of CaCl2 = 0.235 x 0.557 = 0.130895

1 mole of CaCl2 produces 2 moles of AgCl

So 0.130895 moles of CaCl2 will produce 2 x 0.130895

= 0.26179 moles of AgCl

b) Molar mass of AgCl = 143.32 g/mol

So the amount of AgCl produced = 143.32 x 0.26179

= 37.52 grams