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Starting Materials: 0.25 4-Aminobenzoic Acid mL; _moles Ethyl Alcohol 2.5 mL; moles BA 0.3 Conc. H2SO4 mL; moles Product: 0.0
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mass Solution given, of 4-aminobenzoic acid Volume of ethyl alcohol Volume of conc- H₂SO4 0.25g = 2.5mL 0.3mL 0.08g isolatedhass moles of 4-amino benzoic acid = 0.25g (malarmass = 137g/mical moles) 0.00182mcel males of ethylakohal = 1.97259 46 g/mol% yield = 26.58% density of conc. H2SO4 = 1.84 g/mL mass of Conc. H₂SO4 = 1.84 g x 0.3 mL ml = 0.5529 Melasmass of Conc- H2SO

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Starting Materials: 0.25 4-Aminobenzoic Acid mL; _moles Ethyl Alcohol 2.5 mL; moles BA 0.3 Conc. H2SO4...
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