Question

2. If the volume of a gas increases by AV (liters) against a constant restraining pressure P (atm), the work transferred from the system (the gas) to its surroundings is PAV (liter atm) a. Work has units of energy but liter atm is not a convenient unit. Show how to convert 1.00 liter atm to joules (J). b. Suppose 201 cal are transferred to a gas in a balloon (as heat) and the gas expands What is the energy balance? c. For the situation in part (b), if the work done by the expanding gas is 3.62 liter atm, what is AU?

Answer 1

Solution @ @ I L atm = 1x 10-3m% atm = 10-3m%x101325 Pa (: We Know 1L = 10-8 m3) (: 1 atm = 101325Pa) (1 Pa = 1 Must) W=Fd = 101.325 m3 Pa = 101:32 (1J = 1Nm = 101.325 Nm chantier L atm = 101-325) Afloor. After Salonen Balloon 2 Heat In ③ # Applying Energy Balance Energy (feat) In - Energy out + Energy - Energy State 1 - Cenerated consumed = Accumulation Slate 2 # Energy In =Q # Energy out = W (Because ax heat given to the balloon gas) ' expands of we get energy out in / S form of work as PAV. # AE = Energy Accumulation or Energy Stored in gystem - #1Q-W = DE) — @

- Energy stored AE = Emarso + Emicro = (EKTE > Internal energy & it is absolute Value es not generally found but easy to find change. for Ideal gas ů > f (Temß) When system es stationary & neglect the effect of goalety then DE = het to tau LAB = AU 1. So from equr 9 18-W = AV som

2 © Q = 201 cal (given in 2 ) Q =2018 4.18 J I Cal = 4.18 J Q = 840.18 J Calculated in 2@ W = 3.62 Latm = 3.62x101.325J (ILatm = 101-325J) W = 366.7965J # We Know Q-W= AV AU = (840-18 – 3 66.7965)J AU = 473.3835 J Showerca U = 473.45] Afforox

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