A. You wish to test the following claim (HaHa) at a significance level of α=0.10α=0.10. Ho:μ=57.1Ho:μ=57.1. Ha:μ<57.1Ha:μ<57.1. You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data:
Column A | Column B | Column C | Column D | Column E |
---|---|---|---|---|
30.1 | 75.6 | 53.5 | 84.7 | 59.2 |
37.2 | 36.5 | 52.7 | 47.3 | 70.9 |
34.9 | 44.3 | 37.2 | 43.8 | 46.8 |
48.2 | 60.6 | 49.6 | 61.5 | 74.7 |
39.8 | 39.8 | 34.1 | 57.9 | 44.8 |
56.1 | 68.4 | 64.5 | 78.7 | 84.7 |
14.2 | 62 | 42.7 | 73.9 | 50.9 |
24.1 | 59.7 | 53.5 | 51.4 | 54 |
42.7 | 33.2 | 63.5 | 86.9 | 55.3 |
56.6 | 42.7 | 55.7 | 38.6 | 26 |
What is the test statistic for this sample? (Report answer
accurate to three decimal places.)
test statistic =
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
B. A well-known brokerage firm executive claimed that at least 64 % of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that out of 64 randomly selected people, 39 of them said they are confident of meeting their goals. Suppose you are have the following null and alternative hypotheses for a test you are running: H0:p=0.64H0:p=0.64. Ha:p≠0.64Ha:p≠0.64. Calculate the test statistic, rounded to 3 decimal places. z=
C. Based on a sample of 25 people, the sample mean GPA was 2.66 with a standard deviation of 0.07. The test statistic is: (to 2 decimals). The critical value is: (to 2 decimals)
D. You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05. Ho:μ=60.2Ho:μ=60.2. Ha:μ<60.2Ha:μ<60.2. You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data:
Column A | Column B | Column C | Column D |
---|---|---|---|
56.6 | 45.9 | 52.9 | 57.3 |
62.7 | 53.9 | 43.9 | 54.6 |
42.6 | 68.5 | 55.2 | 45.5 |
67.3 | 39.7 | 67.3 | 42.6 |
49.9 | 66.1 | 58.8 | 53.9 |
55.9 | 42.2 | 56.3 | 52.9 |
29.6 | 70.7 | 45.5 | 43.9 |
What is the critical value for this test? (Report answer
accurate to three decimal places.)
critical value =
What is the test statistic for this sample? (Report answer accurate
to three decimal places.)
test statistic =
Answer:
A. You wish to test the following claim (HaHa) at a significance level of α=0.10α=0.10. Ho:μ=57.1Ho:μ=57.1. Ha:μ<57.1Ha:μ<57.1. You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data:
Column A |
Column B |
Column C |
Column D |
Column E |
---|---|---|---|---|
30.1 |
75.6 |
53.5 |
84.7 |
59.2 |
37.2 |
36.5 |
52.7 |
47.3 |
70.9 |
34.9 |
44.3 |
37.2 |
43.8 |
46.8 |
48.2 |
60.6 |
49.6 |
61.5 |
74.7 |
39.8 |
39.8 |
34.1 |
57.9 |
44.8 |
56.1 |
68.4 |
64.5 |
78.7 |
84.7 |
14.2 |
62 |
42.7 |
73.9 |
50.9 |
24.1 |
59.7 |
53.5 |
51.4 |
54 |
42.7 |
33.2 |
63.5 |
86.9 |
55.3 |
56.6 |
42.7 |
55.7 |
38.6 |
26 |
What is the test statistic for this sample? (Report
answer accurate to three decimal places.)
test statistic = -2.164
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =0.0177
t Test for Hypothesis of the Mean |
|
Data |
|
Null Hypothesis m= |
57.1 |
Level of Significance |
0.05 |
Sample Size |
50 |
Sample Mean |
52.114 |
Sample Standard Deviation |
16.29478457 |
Intermediate Calculations |
|
Standard Error of the Mean |
2.3044 |
Degrees of Freedom |
49 |
t Test Statistic |
-2.1637 |
Lower-Tail Test |
|
Lower Critical Value |
-1.6766 |
p-Value |
0.0177 |
Reject the null hypothesis |
B. A well-known brokerage firm executive claimed that at least 64 % of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that out of 64 randomly selected people, 39 of them said they are confident of meeting their goals. Suppose you are have the following null and alternative hypotheses for a test you are running: H0:p=0.64H0:p=0.64. Ha:p≠0.64Ha:p≠0.64.
Calculate the test statistic, rounded to 3 decimal places. Z = -0.510
Z Test of Hypothesis for the Proportion |
|
Data |
|
Null Hypothesis p = |
0.64 |
Level of Significance |
0.05 |
Number of Items of Interest |
39 |
Sample Size |
64 |
Intermediate Calculations |
|
Sample Proportion |
0.609375 |
Standard Error |
0.0600 |
Z Test Statistic |
-0.5104 |
Two-Tail Test |
|
Lower Critical Value |
-1.9600 |
Upper Critical Value |
1.9600 |
p-Value |
0.6098 |
Do not reject the null hypothesis |
C. Based on a sample of 25 people, the sample mean GPA was 2.66 with a standard deviation of 0.07. The test statistic is: (to 2 decimals). The critical value is: (to 2 decimals)
Critical value at 0.05 level =2.06
Critical value at 0.01 level =2.80
D. You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05. Ho:μ=60.2Ho:μ=60.2. Ha:μ<60.2Ha:μ<60.2. You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data:
Column A |
Column B |
Column C |
Column D |
---|---|---|---|
56.6 |
45.9 |
52.9 |
57.3 |
62.7 |
53.9 |
43.9 |
54.6 |
42.6 |
68.5 |
55.2 |
45.5 |
67.3 |
39.7 |
67.3 |
42.6 |
49.9 |
66.1 |
58.8 |
53.9 |
55.9 |
42.2 |
56.3 |
52.9 |
29.6 |
70.7 |
45.5 |
43.9 |
What is the critical value for this test? (Report answer
accurate to three decimal places.)
critical value =-1.703
What is the test statistic for this sample? (Report answer
accurate to three decimal places.)
test statistic =-3.832
t Test for Hypothesis of the Mean |
|
Data |
|
Null Hypothesis m= |
60.2 |
Level of Significance |
0.05 |
Sample Size |
28 |
Sample Mean |
52.93571429 |
Sample Standard Deviation |
10.03158768 |
Intermediate Calculations |
|
Standard Error of the Mean |
1.8958 |
Degrees of Freedom |
27 |
t Test Statistic |
-3.8318 |
Lower-Tail Test |
|
Lower Critical Value |
-1.7033 |
p-Value |
0.0003 |
Reject the null hypothesis |
A. You wish to test the following claim (HaHa) at a significance level of α=0.10α=0.10. Ho:μ=57.1Ho:μ=57.1....
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