What is the least common multiply that will eliminate the denominator in 1 +2 -3? Solve...
2/10 To rationalize the denominator of , 1. you should multiply the expression by which fraction? /10 10 11 11 2-10 2-10 3-11 3-11
Simplify the complex rational expression using the least common denominator. + x+6 + I (Use integers or fractions for any numbers in the expression.) 1+ 1+x+6 1 Solve the proportion. 26 x 13 9 The solution set is { }. (Simplify your answer. Use a comma to separate answers as needed.) Simplify the rational expression. Assume that no variable has a value which results in a denominator with a value of zero. y2 - 13y + 40 y? - 12y...
Assume that the expressions given are denominators of fractions. Find the least common denominator (LCD) for the group. ² - 36, 2y + 12, y The LCD is
Find the least common denominator of the rational expressions. Then rewrite each rational expression with the LCD 77x-18 and X2-17x + 72
If we want to solve the following system using the elimination method, we can multiply the first equation by ____ and the second equation by ____, to eliminate the y. 6x + 15y = 7 9x + 3y = 8 a. 3,2 b. 5,1 c. -3, -2 d. -1, 5
) Compute п 1 E k=1 kvk +1+(k+1) VK Hint: rationalize the denominator, i.e. multiply by kvk +1 – (k+1) Vk both the numerator and denominator.
Which of the following pairs of fractions with a common denominator are equivalent to 1/4 and 2/5Seven more than twice a number is equal to twenty-one Which of the following equations expresses the phrase above?
State what x represents, write an equation, and answer the question In a certain fraction, the denominator is 2 less than the numerator. If 1 is added to both the numerator and denominator, the resulting fraction is equal to. What was the original fraction? Which of the following would make a good choice for x? the numerator the resulting fraction the number added O the original fraction Translate the given statements into an equation that can be used to solve...
structural analysis solve for reaction forces please multiply the load by 2 beforw solving (it will be 200KN) l0o 3h 51 4 2
why did they multiply by 3 why not 2 how do we know what nunber to multiply by Combustion of a hydrocarbon: CH,+ 02 → CO2 + H20 X V 1.59 g 5.11 g 1.74 g Atom Grams 1.395 g C 0.195 g H Moles 1.395/(12.011) = 0.116 0.116/0.116 = 1 x3 0.195/(1.008) = 0.195 0.195/0.1169 = 1.67 x 3 EF mole Ratio C₂H,