We have
But we know that
Thus, for each mole of C, we have moles of H.
The denominator in is 3. To make a whole number, we need to multiply it with denominator (3).
why did they multiply by 3 why not 2 how do we know what nunber to multiply by Combustion of a hydrocarbon: CH,+ 02...
2C +02 2Pb + O2 → 2CO) → 2P50) Eqs. 7.1 reactants products CH, + 2O + co, + 2H2O methane oxygen water C: carbon dioxide C: H: 2 x 2 O: 2 + 2 H: 4 4 1 = 4 = 4 O: 2 x 2 = Figure 7.4. A balanced chemical reaction with stoichiometric conventions noted. Question 7.4. Balance the following chemical reactions: a) CH4 +_2_02 _CO2 + 2 H20 b) CH-OH + 02 → CO2 + H2O...