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Conversion of 0 80 g of Iiquid water to steam at 1 Plz help?
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Answer #1

Now calculate the number of moles of H2O:

Molar mass of H2O = 18.02 g/mol

Number of moles = 0.80 g H2O /18.02 g/mol

= 0.044 mol H2O

Given that dH = 1.8 kJ

Molar heat of evaporation = total heat / number of moles

= 1.8 kJ/ 0.044 mol

= 40.9 kJ/mol

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