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calculate the molar heat capacity Cm for water. you knew that 30.1 kJ was required to...

calculate the molar heat capacity Cm for water. you knew that 30.1 kJ was required to heat 10.0 g of ice from 0.00 C to steam 100.00 C and that the melting point pin ∆fusH = 6.01 kJ / mol and the evaporating enthalpy ∆vapH = 40.7 kJ / mol.

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Mass a water = 10 g molas mass of water = 18 g/mol mole of wata = mass mokes mass = 10 If Cm ix Heat capacity per mole Heat B100 lk) 47 - 373(k) – 273(k) - Put all Value 30.1 = (6:01) x0.5555) + (0:5555) Cm (100) + (0.5555)(40.7) 30.1 = 3+3385 + 55.5

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