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Determine the tension of CB (in Ib) in the cables necessary to hold the 83-lb sign in equilibrium. The center of gravity for

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Answer #1

Sols 2 1 - м. (Maly 23 % 2 FDE TOE ( 2 / 2 TBC = TBC (-2/ * * * ) * ) . 4,0 ; ToE Tect Ax=0 TDE - 2 TBC + Ay=0 fo 3fo : ат» *

On solving the above equations 2 , we get Ал- — до -12 10 Ay=0 Toc 6. а. ЛЬ Това ба- аа ль (Hд, о. 12 hi- (Maly = 83 +4 : Том

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