Question

11. (6 points) A He* ion in its ground state absorbs a photon of energy 51.0 eV. Which atomic orbital(s) may serve as the final state after the excitation? (i.e. after absorption of 51.0 eV, what excited orbital orbital(s) is the electron in?)

Answer 1

For hydrogen live atom the energy level is given by E_n = -Z^2/h^2 13.6 e v where z = atomic rules n = Quinton states now for He^+ ion z = 2 ground state E_0 = -4 times 13.6 = -54.4 ev after absorbs an energy = 51 e v the new energy of the system = -54.4 + 51 = -3.4 e v let the n^th state E_n = -3.4 = -54.4/n^2 therefore n^2 = 54.4/3.4 = 16 therefore n = 4 therefore the electron given on the 4^th energy level or 3^rd excited state orbit