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A rocket is launched vertically from the origin. For the time from t=0s to 5.5s it has a constant acceleration of a =5.7 k A

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Answer #1

From t=0 to t= 5.55 using Sy = uzt + azt ² Sz= 0 + ₂ x 5.7 x 5.5² S2= 86.2125 ml After t = 5.55 = ut at V₂ = 5.7 x 5.5 = 31.3

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