A 1000 kg weather rocket is launched straight up. The rocket motor provides a constant acceleration for 16 s, then the motor stops. The rocket altitude 20 s after launch is 6600 m.You can ignore any effects of air resistance.
What was the rocket's acceleration during the first 16 s?
Express your answer with the appropriate units.
A 1000 kg weather rocket is launched straight up. The rocket motor provides a constant acceleration...
A 1000 kg weather rocket is launched straight up.The rocket motor provides a constant acceleration for 16 s, then the motor stops. The rocket altitude 20 s after launch is 6200 m. You can ignore any effects of air resistance. What was the rocket's acceleration during the first 16s? What is the rocket's speed as it passes through acloud 6200 m above the ground?
Review Part A A 1000 kg weather rocket is launched straight up. The rocket motor provides a constant acceleration for 16 s, then the motor stops. The rocket altitude 20 s after launch is 7100 m. You can ignore any effects of What was the rocket's acceleration during the first 16 s? Express your answer with the appropriate units air resistance al x.10" | a= | Value Units Submit Previous Answers Request Answer A student standing on the ground throws...
Please solve step by step using an analytical solution before plugging in any numbers 20. A 1000 kg weather rocket is launched straight up. The rocket motor provides a constant acceleration for 16 s, then the motor stops. The rocket altitude 20 s after launch is 5100 m. You can ignore any effects of air resistance. What was the rocket's acceleration during the first 16 s?
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Need help in solving this problem a 2220-kg test rocket is launched vertically from the launch pad. Its fuel (of negligible mass) provides a thrust force so that its vertical velocity as a function of time is given by v(t)=At+Bt2, where A and B are constants and time is measured from the instant the fuel is ignited. At the instant of ignition, the rocket has an upward acceleration of 1.20 m/s2 and 1.80 s later an upward velocity of 1.64...
A model rocket is launched with a very rapid engine burst. The engine cuts off quickly and the rocket is subject only to gravity after that (ignore air resistance). At t=0, (which we call height=0) it is heading straight up with an initial speed of 52 m/s . We define "up" as the positive direction. Find the rocket's altitude at 7 s?. It says its incorrect but i got: 123.9m 52(7)-1/2 * 9.8(7)^2 = 123.9m